Posted 07 May 2011 - 10:51 PM
Dilligaf, I can see why you think that the ballast wire is fused, but like Steve and I said, it is not.
Yes, there is fuse #48 shown in your schematic. However, you have to look at what happens if you remove that fuse. The white wire gets power from the ignition switch (unfused). If you remove fuse #48, the pink/white wire still gets power... it is the GREEN wires on the left side of fuse #48 that become "dead". The fuse protects the "green" wires, not the white or pink/white.
Regarding fusing the Ignitor, when you put an inline fuse on the module's RED wire, that protects nothing. As I said earlier, that fuse would need to blow at very low current because the only draw on the red wire would be the current required by the electronics inside the module. If you fuse the ballast wire, you will need to select a fuse that will not blow in response to inrush currents. I have no idea what that would require. That's a calculation for an electrical engineer.
TheOldOne, checks with a multimeter will quickly tell you what ignition system you have. Mark and disconnect the coil low tension wires. Measure the resistance in Ohms across the coil's low tension terminals. If you find 1-2 Ohms, you have a ballast coil. If you measure about 3 Ohms you have a standard coil. Put the wires back on and place a coin between the points under the dizzy cap. Set your meter to measure volts and and turn the ignition switch to the run position. Measure between the coil (+) terminal and earth. If you measure about 12V, you have wiring for a standard coil. If you measure 6-9 Volts, the wiring is for a ballast coil. (The coil (+) terminal will be the one that DOES NOT have the white/black wire on it.)