26 replies to this topic

[jim4eva]

In a cody format

if( cc < 900 ){
car = "under 1 litre"
}

if( cc > 900 AND cc < 1050){
car = "1 litre"
}

if( cc > 1050 AND cc < 1125){
car = "1.1 litre"
}

if( cc > 1125 AND cc < 1260){
car = "1.2 litre"
}


if( cc > 1260 AND cc < 1320){
car = "1.3 litre"
}


need that up to a 3litre really - but under the 2litre would be the most used i imagine

Something like that would work. It doesnt need to be accurate, just a best guess. As if the person enters 1275, it will be converted to 1.3 in the database. If someone entered say 1.25 like 998dave said, then it would be a 1.2 litre .... would this work?

Does that make sense? Apologies for sudocode it seemed easier

if it doesnt have to be accurate then how about this:

if( cc < 950 ){
car = "under 1 litre"
}

if( cc > 950 AND cc < 1049){
car = "1 litre"
}

if( cc > 1050 AND cc < 1149){
car = "1.1 litre"
}

if( cc > 1150 AND cc < 1249){
car = "1.2 litre"
}


if( cc > 1250 AND cc < 1349){
car = "1.3 litre"
}

if( cc > 1350 AND cc < 1449){
car = "1.4 litre"
}

if( cc > 1450 AND cc < 1549){
car = "1.5 litre"
}

if( cc > 1550 AND cc < 1649){
car = "1.6 litre"
}

and just keep going as high as you like.

I still dont understand why you would want to do this though?

GL1

I'm glad to see that we have a programming community among mini owners ...
also I'm sure you know this but I thought I'd say it any way... and in programming can be symbolized with || ...
sorry if that's painfully obvious

[greenlaner1]

I'm glad to see that we have a programming community among mini owners ...
also I'm sure you know this but I thought I'd say it any way... and in programming can be symbolized with || ...
sorry if that's painfully obvious

I work mainly with ladder logic so most of this stuff is foreign to me

is it just me or does this seem like something really very simple that has been made complicated?

GL1

[Dan]

2 significant figures....

GL1

Yes sorry, meant to say one significant figure after the decimal!

Actually I would say the 850 should be called a 0.9, it would be if it was launched today. Manufacturer's play all kinds of tricks with engine sizes. Fiat for example used to sell the exact same engine as two different sizes in two different countries to take advantage of engine displacement tax breaks from the two different governments. Other companies have done similar things and it's all just done by playing with the maths. They should really just all be rounded according to the accepted conventions of mathematics.

[jim4eva]

I'm glad to see that we have a programming community among mini owners ...
also I'm sure you know this but I thought I'd say it any way... and in programming can be symbolized with || ...
sorry if that's painfully obvious

I work mainly with ladder logic so most of this stuff is foreign to me

is it just me or does this seem like something really very simple that has been made complicated?

GL1

it is... you could use a switch statement which would make it much easier

[zelliott]

Well the smallest car Ive heard of in 50cc
And the biggest is 27 litres

and theres just anout everythign in between too (:

[chrisandsarah]

if it doesnt have to be accurate then how about this:

if( cc < 950 ){
car = "under 1 litre"
}

if( cc > 950 AND cc < 1049){
car = "1 litre"
}

if( cc > 1050 AND cc < 1149){
car = "1.1 litre"
}

if( cc > 1150 AND cc < 1249){
car = "1.2 litre"
}


if( cc > 1250 AND cc < 1349){
car = "1.3 litre"
}

if( cc > 1350 AND cc < 1449){
car = "1.4 litre"
}

if( cc > 1450 AND cc < 1549){
car = "1.5 litre"
}

if( cc > 1550 AND cc < 1649){
car = "1.6 litre"
}

and just keep going as high as you like.

I still dont understand why you would want to do this though?

GL1

Good idea - cheers! It is for a project - more because I want to allow people to have the choice of entering their cc aswell as say 1.2 because I dont want to have a dropdown with .9l 1l 1.1l etc

[chrisandsarah]

I'm glad to see that we have a programming community among mini owners ...
also I'm sure you know this but I thought I'd say it any way... and in programming can be symbolized with || ...
sorry if that's painfully obvious

haha - yeah it was just sudo code for non programming people - thought it would be easier to understand than writing out a switch / case or full blown if statements.

it will all make sense when it is complete hopefully it is a project that everyone can make some use of

[oli8925]

As Dan says, manufacturers fiddle it a lot anyway depending on the market criteria.

Also if you want to do the list properly, you should list the engine sizes in 'ci' too. Most of my workshop manuals for the Viva list the engine size in ci. The difference between tiny British engines and huge Amercan V8s seems even bigger in ci. Chevy big block - 427ci (up to 572 released in '03). My 1256 Viva - 76.6ci

998cc = 60.9ci
1275cc = 77.8ci

[chrisandsarah]

As Dan says, manufacturers fiddle it a lot anyway depending on the market criteria.

Also if you want to do the list properly, you should list the engine sizes in 'ci' too. Most of my workshop manuals for the Viva list the engine size in ci. The difference between tiny British engines and huge Amercan V8s seems even bigger in ci. Chevy big block - 427ci (up to 572 released in '03). My 1256 Viva - 76.6ci

998cc = 60.9ci
1275cc = 77.8ci

Hmm a little more in depth than I am wanting - but I didn't know that!!! cheers

[Deathrow]

Do as Dan suggested. In Java:

double userIn = 1275;
		
System.out.println("User entered " + (int)userIn + "cc's.");
		
//Share by 1000 and round.
DecimalFormat twoDForm = new DecimalFormat("#.#");
double litres = Double.valueOf(twoDForm.format(userIn/1000));
		
System.out.println("That's " + litres + "l.");

Output:

User entered 1275cc's.
That's 1.3l.

Note that the last character before the period is an l, not a 1.

Please lord don't use a massive switch statement, the cyclomatic complexity would be horrific.

[chrisandsarah]

......
Note that the last character before the period is an l, not a 1.

Please lord don't use a massive switch statement, the cyclomatic complexity would be horrific.

I am so thick! Did not think of doing it at way at all - you know when you puzzle over something silly for so long that you can no longer see a sensible answer, my Java days have long gone, but in PHP it would be...

$cc = "1598";
$newCC = number_format(($cc/1000), 1, '.', '');
echo &#34;The &#34;.$cc.&#34;cc engine is actually a &#34;.$newCC.&#34;<br />&#34;;

Edited by chrisandsarah, 03 June 2011 - 10:32 AM.

[Cerberus]

In a cody format

if( cc < 900 ){
car = "under 1 litre"
}

if( cc > 900 AND cc < 1050){
car = "1 litre"
}

if( cc > 1050 AND cc < 1125){
car = "1.1 litre"
}

if( cc > 1125 AND cc < 1260){
car = "1.2 litre"
}


if( cc > 1260 AND cc < 1320){
car = "1.3 litre"
}


need that up to a 3litre really - but under the 2litre would be the most used i imagine

Something like that would work. It doesnt need to be accurate, just a best guess. As if the person enters 1275, it will be converted to 1.3 in the database. If someone entered say 1.25 like 998dave said, then it would be a 1.2 litre .... would this work?

Does that make sense? Apologies for sudocode it seemed easier

if it doesnt have to be accurate then how about this:

if( cc < 950 ){
car = "under 1 litre"
}

if( cc > 950 AND cc < 1049){
car = "1 litre"
}

if( cc > 1050 AND cc < 1149){
car = "1.1 litre"
}

if( cc > 1150 AND cc < 1249){
car = "1.2 litre"
}


if( cc > 1250 AND cc < 1349){
car = "1.3 litre"
}

if( cc > 1350 AND cc < 1449){
car = "1.4 litre"
}

if( cc > 1450 AND cc < 1549){
car = "1.5 litre"
}

if( cc > 1550 AND cc < 1649){
car = "1.6 litre"
}

and just keep going as high as you like.

I still dont understand why you would want to do this though?

GL1

I'm glad to see that we have a programming community among mini owners ...
also I'm sure you know this but I thought I'd say it any way... and in programming can be symbolized with || ...
sorry if that's painfully obvious

|| = 'OR'
&& = 'AND'
! = NOT

so

if(cc > 1550 && cc < 1649)


if you used || (OR)

you'd end up with everything above 1550 and everything below 1649, so you'd have everything, so that wouldn't work.